Question 193575
One leg of a right triangle is 96 inches. Find the hypotenuse and the
 other leg if the length of the hypotenuse exceeds 2 and 1/2 times teh other leg by 4 inches. 
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One leg is 96 in
Let the "other leg" be "x" inches.
hypotenuse  = (5/2)x + 4
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Equation:
h^2 = leg^2 + "otherleg"^2
[(5/2)x + 4]^2 = 96^2 + x^2
[(5x+ 8)/2^2 = 96^2 + x^2
(5x+8)^2 = 4*96^2 + 4x^2
25x^2 + 90x + 91 = 36864 + 4x^2
21x^2 + 90x - 36773 = 0
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Positive solution:
x = 39.76
hypotenuse = (5/2)x+4 = 103.4
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Cheers,
Stan H.