Question 193531
{{{8y=-x^2-4x+4}}}
:
{{{8y=-1(x^2+4x+4)+4-4}}}
:
{{{8y=-1(x+2)^2}}}
:
{{{y=(-1/8)(x+2)^2}}}
:
a=coefficient of {{{x^2}}} term so a=-1/8
:
so vertex is (-2,0)
focus is (-2,0+1/4a)-->1/4a=1/(4(-1/8)=1/(-1/2)=-2--> (-2,-2)
:
directrix is at y=-1/4a=-1/4(-1/8)=-1/(-1/2)=2 so y=2
:
axis of symmetry is x=-2
:
{{{graph(300,300,-10,10,-10,10,(-1/8)(x+2)^2)}}}