Question 193522
{{{root(5,-32x^5y^6)}}} Start with the given expression



{{{root(5,(-2)^5*x^5y^6)}}} Rewrite {{{-32}}} as {{{(-2)^5}}}



{{{root(5,(-2)^5*x^5*y^5*y)}}} Factor {{{y^6}}} to get {{{y^5*y}}}



{{{root(5,(-2)^5)*root(5,x^5)*root(5,y^5)*root(5,y)}}} Break up the root



{{{-2*root(5,x^5)*root(5,y^5)*root(5,y)}}} Take the 5th root of {{{(-2)^5}}} to get -2



{{{-2x*root(5,y^5)*root(5,y)}}} Take the 5th root of {{{x^5}}} to get "x"



{{{-2xy*root(5,y)}}} Take the 5th root of {{{y^5}}} to get "y"



So {{{root(5,-32x^5y^6)=-2xy*root(5,y)}}}