Question 193459
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Given Eqns.
{{{system(6x-4y = 12(red(EQN1)),-4y + 2y = -6(red(EQN2)))}}}


In {{{red(EQN1)}}}, Let Fy=0:
{{{6x-4(0)=12}}}
{{{cross(6)x/cross(6)=cross(12)2/cross(6)1}}}
{{{red(x=2)}}}, X-Intercept
Let Fx=0:
{{{6(0)-4y=12}}}
{{{cross(-4)y/cross(-4)=cross(12)3/cross(-4)1}}}
{{{red(y=-3)}}}, Y-Intercept


In {{{red(EQN2)}}}, we can see it's horizontal line in the form "y=c"
Continuing,
{{{-4y+2y=-6}}}
{{{-2y=-6}}} ---> {{{cross(-2)y/cross(-2)=cross(-6)3/cross(-2)1}}}
{{{red(y=3)}}}
Slope is undefined


We see graph,
{{{drawing(400,400,-6,6,-6,6,graph(400,400,-6,6,-6,6,(6x-12)/4,3),blue(circle(2,0,.08)),blue(circle(0,-3,.08)),blue(circle(0,3,.08)))}}} ----> {{{red(RED=EQN1)}}}; {{{green(GREEN=EQN2)}}}


Thank you,
Jojo</font>