Question 193398
*The difference of two integers is 20. The larger is 4 less than 3 times the smaller. Find the two integers.*
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Let x = larger of the two integers
and y = smaller of the two integers
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x-y=20    (equation 1)
x = 3y-4  (equation 2)
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Substitute the value of x from equation 2 into equation 1 and solve for y:
x-y=20
3y-4-y=20
2y-4=20
2y=24
y =  12 
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Substitute the value of y above into equation 2 and solve for x:
x = 3y-4
x = 3(12)-4
x = 36-4
x = 32
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Our two integers are 12 and 32