Question 193381
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1a. Correct.


1b. You calculated the discriminant correctly, but interpreted the results incorrectly.  You said that there are no defined solutions.  In fact, there are no <i>real number</i> solutions.  However, there is a conjugate pair of complex solutions -- see your answer to #3.  Even if your instructor wanted you to answer "No solution" to these, you should still say "No real number solution"


1c. Can't help you with this one.  You didn't include the problem.


1d. Almost correct.  You should say that there is one real number solution with a multiplicity of 2.


1e. Same answer as 1b.


1f. Correct.


1g. Same answer as 1b.


1h. Same answer as 1d.


2. If -3 and 4 are solutions, then *[tex \LARGE x = -3 \ \ \Rightarrow\ \ x + 3 = 0] and *[tex \LARGE x = 4 \ \ \Rightarrow\ \ x - 4 = 0] are the factors of the quadratic trinomial, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x + 3)(x - 4) = x^2 - x - 12 = 0]


3.  Correct


4.  Correct


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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