Question 193099
{{{y=-(x^2-6x+9)+9-14}}}
:
{{{y=-1(x-3)^2-5}}}
:
vertex is a (3,-5)
:
axis of symmetry is x=3
:
focus is at 1/4a=-1--->-4a=1-->a=-1/4 so focus is at (3,-21/4)
:
latus rectum is {{{abs(4(-1/4))}}}=1