Question 193122
log(x+9)=1-logx
log(x+9) +logx=1
to  multiply  is  to  add  logs
log(x+9)*(x)=1
log(x^2+9x)=1
raise  both  sides  as  power  of  10
10^log(x^2+9x)=10^1
(x^2+9x) =10
x^2+9x-10=0
(x+10)(x-1)=0
x=1, and  -10  (not  realistic  answer,  no  log(- number)
check  x=1
log(1+9)=1-log1
log10=1-log1
1=1-0  ok