Question 193116
Directions is solve for y in terms of x.
log10y = log10 7-3 log10(x-7). This is what I have done. 
log10y = log10 7-3 log10 (x-7). I canceled out the log10 and was left with.
y=x/3 then convert to y=x3. Is this correct? 
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{{{log(y) = log(7) - 3log(x-7)}}}
{{{log(y) = log((7/(x-7)^3))}}}
{{{y = 7/(x-7)^3}}}