Question 193101
{{{40x^2-48x-88}}}
{{{5x^2 - 6x - 11 = 0}}} (I assume you want the roots)
Use quadratic equation
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a = 5}}}
{{{b= -6}}}
{{{c = -11}}}
{{{x = (-(-6) +- sqrt( (-6)^2-4*5*(-11) ))/(2*5) }}}
{{{x = (6 +- sqrt( 36 + 220 ))/10 }}}
{{{x = (6 +- sqrt( 256 ))/10 }}}
{{{x = (6 +- 16)/10 }}}
The 2 roots are:
{{{x = (6 + 16)/10}}}
{{{x = 22/10}}}
and
{{{x = (6 - 16)/10}}}
{{{x = -1}}}
I checked these answers - OK