Question 193049
 what is the area of a regular hexagon whose sides are each 12 inches long. Round to the nearest squre inch. I drew the figure. used this formula: A=4 + 2, A=6. Or should it be 360 
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If you draw lines from the center to each vertex, the hexagon is made up of 6 equilateral triangles, 12" on a side.
The height of the triangle is sqrt(12^2 - 6^2) = sqrt(108)
The area of one triangle is bh/2 = 12*sqrt(108)/2 = 6sqrt(108)
There are 6, so the total area is 36sqrt(108)
= 216sqrt(3)
= ~ 62 sq inches