Question 192831
Ans: 1.25 pm
Let.
D = distance from Station A, at which both trains meet.

Train B passes Station A - 12 mins after Train A
In 12 mins Train A has travelled 16 miles.
So, when Train B is at Station A
Train A has travelled 16 miles ahead. The distance remaining is D - 16

Time taken by Train B (t2) to reach meeting point is same as time taken by Train A (after a 16 mile lead)to reach meeting point.


t1 = (D-16) / 80    (Train A has a lead of 16 miles)
t2 = D/100

since t1 = t2
80D = 100(D-16)
8D = 10D - 160
D = 80
Train B can complete 80miles in 80*60/100 = 48 mins.
Thus the trains meet at time 12.37 PM + 48 mins = 1.25 PM