Question 192868
*[Tex \LARGE f^{-1}(x)=x^3-8] Start with the given inverse function.



*[Tex \LARGE x=\left(f^{-1}(x)\right)^3-8] Switch "x" and *[Tex \LARGE  f^{-1}(x)].



*[Tex \LARGE x=\left(f(x)\right)^3-8] Replace  *[Tex \LARGE  f^{-1}(x)] with *[Tex \LARGE  f(x)].



*[Tex \LARGE x+8=\left(f(x)\right)^3] Add 8 to both sides.



*[Tex \LARGE \sqrt[3]{x+8}=f(x)] Take the cube root of both sides.



So the inverse of the given inverse (or simply the original function) is *[Tex \LARGE f(x)=\sqrt[3]{x+8}].