Question 192845
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One leg of your triangle is <b><i>x</i></b>, the other leg of your triangle is <b><i></i>22</b>, and the hypotenuse is <b><i>x</i> + 16</b>.


Pythagoras says:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x + 16)^2 = x^2 + 22^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + 32x + 256 = x^2 + 484]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 32x = 228]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = 7.125]


Check:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (7.125 + 16)^2 =^? (7.125)^2 + 22^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 534.765625 =^? 50.765625 + 484]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 534.765625 = 534.765625]  Answer checks.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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