<PRE><B>Question 192875</B>
An express train and a local train both leave Gray’s Lake at 12:00 noon and head for Chicago 60 miles away. The express travels twice as fast as the local and arrives 2 hours ahead of it. Find the speed of each train. 
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Express DATA:
distance = 60 miles ; rate = 2x mph ; time = d/r = 60/2x = 30/x hr.
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Local DATA:
distance = 60 miles ; rate = x mph ; time = 60/x hr.
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Equation:
local train time - express train time = 2 hrs
60/x - 30/x = 2
60 - 30 = 2x
2x = 30
x = 15 mph (local train speed)
2x = 30 mph (express train speed)
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Cheers,
Stan H.</PRE>