Question 192820
let amount of materal be a and let the diameter be d
:
{{{a/d^2=k}}} where k is the constant of variation
:
{{{452/12^2=k}}} k=3.14
:
{{{1017/d^2=3.14}}} --->{{{d^2=1017/3.14}}}-->{{{d^2=323.89}}}
:
{{{d=sqrt(323.89)}}}=18 cm