Question 192640
Suppose that a corporation that manufactures widgets determines that
 its revenue function is R(x)=1000x-x^2 and its cost function is C(x)=3000+20x,
 where x represents the number of widgets produced. 
Find the corporation's maximum profit.
:
Profit = Revenue - cost
therefore:
P = (1000x - x^2) - (3000+20x)
P = 1000x - x^2 - 3000 - 20x
P = -x^2 + 980x - 3000; 
A quadratic equation, find the axis of symmetry & maximum using x = {{{(-b)/(2a)}}}
In this equation: a=-1; b=980
x = {{{(-980)/(2*-1)}}}
x = +490 units produce max profit
:
Find max profit using: P = -x^2 + 980x - 3000;
:
P = -(490^2) + 980(490) - 3000
P = -240100 + 480200 - 3000
P = $237,100 is max profit 
:
You can check the math by substituting 490 for x in the original equations