<PRE><B>Question 192574</B>
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If &lt;b&gt;&lt;i&gt;y&lt;/i&gt;&lt;/b&gt; varies directly as &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt;, then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = kx]


Where &lt;b&gt;&lt;i&gt;k&lt;/i&gt;&lt;/b&gt; is the constant of proportionality.


You are given that &lt;b&gt;&lt;i&gt;y&lt;/i&gt; = 21&lt;/b&gt; when &lt;b&gt;&lt;i&gt;x&lt;/i&gt; = 3&lt;/b&gt;


So, just substitute the values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3k = 21]


And solve for the value of &lt;b&gt;&lt;i&gt;k&lt;/i&gt;&lt;/b&gt;.


Now that you have a value for &lt;b&gt;&lt;i&gt;k&lt;/i&gt;&lt;/b&gt;, you can substitute that value and the given value for &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt; back into the original equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = kx]


And your answer is a simple multiplication of 5 times the value you determined for &lt;b&gt;&lt;i&gt;k&lt;/i&gt;&lt;/b&gt;.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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