Question 192244
Apply "log rules":
log3x+log(x+2)=1
log(3x)(x+2)=1
(3x)(x+2)=10^1
3x^2+6x=10
3x^2+6x-10=0
Solve using the quadratic equation:
x = {1.082, -3.082}
We can toss out the negative solution leaving:
x = 1.082
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Details of quadratic to follow:
.
*[invoke quadratic "x", 3, 6, -10 ]