Question 192443
x^2+6x+11=0
x^2+6x   =-11
x^2+6x+9=+9-11 completing the square by (6/2)^2=9
(x+3)^2=-2
x+3=+-sqrt(-2) take sqrt of each side
x=-3+sqrt(2)i, x=-3-sqrt(2)i There are no real number zeroes.
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Ed