<PRE><B>Question 192438</B>
Sweet Harmony Crafts has determined that when x hundred Dobros are built, the average cost per Dobro can be estimated by C(x)=.1x^2-.7x+2.425 where C(x) is in hundreds of dollars. What is the minimum average cost per Dobro and how many Dobros should be built to achieve that minimum?
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C(x)=.1x^2-.7x+2.425 where C(x) is in hundreds of dollars.
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Minimum occurs when x = -b/2a = -[-0.7/(2*0.1)] = 3.5 hundred
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C(3500) = 1.22 million hundred = 1.22*10^8 = 122,000,000 [# of Dobros]
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Cheers,
Stan H.</PRE>