Question 26569
Let the two numbers be a and b.

"The sum of two numbers (a+b) is (=) 90. The second (b) is 10 more (+10) than 4 times the first (4a)"  So b = 4a+10  Puting it all together , you have:

{{{a + b = 90}}}
{{{a + 4a+10 = 90}}} Simplify and solve for a.
{{{5a + 10 = 90}}} Subtract 10 from both sides.
{{{5a = 80}}} Divide both sides by 5.
{{{a = 16}}}

{{{b = 4a+10}}}
{{{b = 4(16)+10}}}
{{{b = 64+10}}}
{{{b = 74}}}

Answer:
The two numbers are: 16 and 74