Question 192333
The larger of two numbers is 1 less than 3 times the smaller. their sum is 63.
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Equations:
x + y = 63
x = 3y-1
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Substitute to solve for "y":
3y-1 + y = 63
4y = 64
y = 16 (the smaller of the two numbers)
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Cheers,
Stan H.