Question 192272
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Let us see the triangle with the dimensions:
{{{drawing(400,400,-2,10,-2,6,triangle(0,0,8,4,8,0),locate(-.5,0,A),locate(8.5,0,C),locate(8,4.5,B),red(locate(1,.5,30^o)),red(locate(7.1,.5,90^o)),red(locate(7,3.5,60^o)),red(locate(8.3,2,a)),red(locate(4,2.5,c)),red(locate(4,-.1,b)))}}}
By Trigo Functions:
{{{sinA=opposite/hypotenus=a/c}}}
{{{red(sin30^o=1/2)=a/c}}}


*Take note: <font color=blue>a=1, c=2, b=?</font>



By Pyth.Theorem:
{{{c^2=a^2+b^2}}}
{{{b^2=c^2-a^2=2^2-1^2=4-1=3}}}
{{{red(b=sqrt(3))}}}


{{{cosA=adjacent/hypotenuse=b/c}}}
{{{red(cos30^o=sqrt(3)/2)}}}



{{{tanA=opposite/adjacent=a/b}}}
{{{red(tan30^o=1/sqrt(3))}}}


Thank you,
Jojo</font>