Question 192306
    The height of a triangle is 4in greater than twice its base. The area of the trianlge is 168 square in. What is the base of the triangle?
.
We know that for any triangle:
area = (1/2)bh
where
b is base
h is height
.
Let b = length of the base
then
2b+4 = length of the height
.
168 = (1/2)b(2b+4)
336 = b(2b+4)
336 = 2b^2 + 4b
0 = 2b^2 + 4b - 336
0 = b^2 + 2b - 168
0 = (b+14)(b-12)
b = 12 inches (base)