Question 192261
log3x+log(x+2)=1
log3x(x+2)=1
3x(x+2)=10^1
3x^2+6x=10
3x^2+6x-10=0
Solving the above using the quadratic equation yields two solutions:
x = {1.082, -3.082}
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Details of quadratic follows:
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*[invoke quadratic "x", 3, 6, -10 ]