Question 192253
The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers. 
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Equations:
x + y = 10
3x = 8y-3
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Substitute to solve for "x":
3x = 8(10-x)-3
3x = 80 - 8x -3
11x = 77
x = 7 (one of the integers)
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Substitute to solve for "y":
7 + y = 10
y = 3(the other integer)
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Cheers,
Stan H.