Question 192253
The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers. 
my try: 
First integer: 3n
Second integer: 8n-3 
3n + 8n-3 = 10 
11n -3 =10 
11n = 13
n = 13/11 
Not right? 
Help! 
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Not much chance it's right since it's not an integer.
smaller integer = s
bigger integer = b
3b+3 = 8s
b+s = 10 --> s = 10-b
Sub for s into 1st eqn
3b+3 = 8*(10-b)
3b+3 = 80-8b
11b = 77
b = 7
s = 3