Question 192230
{{{y=(x^2-6x+9)-9+4}}}
:
{{{y=(x-3)^2-5}}}
:
vertex is (3,-5)
:
y intercept is found by setting x to zero y={{{0^2-6(0)+4}}}=4: (0,4)
:
axis of symmetry is x=3
:
{{{graph(300,300,-10,10,-10,10,x^2-6x+4)}}}