Question 192232
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + 8x + 10 = 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b \pm sqrt{b^2 - 4ac}}{2a} ] where *[tex \LARGE a = 1,\ b = 8,\ c = 10]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-8 \pm sqrt{(8)^2 - 4(1)(10)}}{2(1)} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-8 \pm sqrt{24}}{2} ]


Discriminant: 24 > 0, not a perfect square.  Therefore roots are real, unequal, and not rational.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-8 \pm 4\sqrt{6}}{2} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = -4 \pm \sqrt{6}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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