Question 192195
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What you meant was:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5^{\log_5(x)}]


And here is how you would render such a thing as an input to this site:


5^(log(5,(x)))


Now, for the solution to your problem.  Remember that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = \log_b(x) \ \ \Rightarrow\ \ b^y=x]


But notice that in your problem, you are raising 5 to a base-5 logarithm.  What *[tex \LARGE \log_5(x)] means is "the number I would use as an exponent on 5 to equal <i><b>x</b></i>"  Hence if you raise 5 to the power of the number you would use as an exponent on 5 to equal <i><b>x</b></i>, then you would just get <i><b>x</b></i>.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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