Question 192114
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If *[tex \LARGE  z = -5] or *[tex \LARGE  z = 3]


Then *[tex \LARGE  z + 5 = 0] or *[tex \LARGE  z - 3 = 0]


And these are then the two factors of your quadratic trinomial:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (z + 5)(z - 3) = 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ z^2 + 2z - 15 = 0]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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