Question 187034
2x^-7x-2=0
IF you mean: 2x^2-7x-2=0 then:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(7+-sqrt[-7^2-4*2*-2])/2*2
x=(7+-sqrt[49+16])/4
x=(7+-sqrt65)/4
x=(7+-8.062)/4
x=(7+8.062)/4
x=15.062/4
x=3.77 ans.
x=(7-8.062)/4
x=-1.062/4
x=-.266 ans.