Question 192184
Solve the following for x (use quadratic equation or factor out):
4x^3-8x^2=0
4x^2*(x-2) = 0
x = 0
x = 2
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The other problem was:
5x^2-3x+6=0
My answer was the following:
using the quadratic equation I came out with
3-+SQRT(-3)^2-4(5)(6)/2(5)
= 3-+SQRT111/10 
= {{{(3/10) +- sqrt(-111)/10}}}
= 0.3 +i*sqrt(111)/10
= 0.3 -i*sqrt(111)/10
No real number solutions.
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Since the SQRT of 111 is 10.525 it would not be a R number, thereby No solution either.