Question 25874
The 1st three terms factor as (t-3)^2
So, rewrite the problem as follows:
(t-3)^2 - 25
You now have the "difference of two squares" which factors as follows:
[(t-3)-5][(t-3)+5]
You may rewrite that as:
(t-8)(t+2)
Cheers,
Stan H.