Question 191965
add
3/(x+5) + 8(m^2-25)
Assume you mean
add
{{{3/(m+5)}}} + {{{8/(m^2-25)}}}
m^2 - 25 is the difference of squares and can be factored
{{{3/(m+5)}}} + {{{8/((m-5)(m+5))}}}
therefore the common denominator is: (m-5)(m+5)
{{{(3(m-5) + 8)/((m-5)(m+5))}}}
:
{{{(3m - 15 + 8)/((m-5)(m+5))}}}
:
 {{{(3m - 7)/((m-5)(m+5))}}} 
or
 {{{(3m - 7)/(m^2-25)}}}