Question 191863
{{{((80x^17)^(1/3))/((9yz^(6))^(1/3))}}}
I think by "3rd sqrt" you mean cube root.
I don't know a cube root symbol here, so I used exponent of 1/3.
= {{{(((80x^17))/((9yz^(6))))^(1/3)}}}
= {{{2x^5*(((10x^2))/((9yz^(6))))^(1/3)}}}
= {{{(2x^5/z^2)*(((10x^2))/((9y)))^(1/3)}}}