Question 26516
First, you'll need to find the volume of the cylindrical tank. Then, you'll need to find the density (gallons/cubic foot) of water. Your answer will be the product of these two quantities.
Using: r = 12 ft. and h = 30 ft.

{{{V = (pi)r^2h}}} Using {{{(pi) = 3.14}}} as an approximation.
{{{V = 3.14(12^2)(30)}}}
{{{V = 13564.8}}}cubic feet.

Density of water:
7.48 gallon(U.S. liquid) per cubic foot.

Capacity of tank:
{{{C = (13564.8)(7.48)}}}
C = 101,465 gallons of water.