Question 26403
Yes, it does make sense.  You are being asked to find the "cube root" of {{{27/y^6}}}
The "cube root" sign uses the same "radical" sign as the square root, but with a little 3 in the front.
You can also write the cube root as an exponent, thus:
{{{(27/y^6)^(1/3)}}} You can rewrite this expression as factors.
{{{((3^3)/(y^2)^3)^(1/3)}}} = {{{((3^3)^(1/3))/((y^2)^3)^(1/3)}}} Multiply the exponents to get: {{{3/y^2}}}

The answer is: {{{3/y^2}}}