Question 191539
let  x =  1st  number

second  number  is   (3*x)

third  number  is  (4*x  -3)

if  sum  is  37  then

37  =  (x) +  (3*x)  +  (4*x-3)  =  8*x  -3

add  3  to  both  sides

40  =  8*x

divide both  sides  by  8

x =  5


check   ist  (5)   2nd(  3*5)  or  (15),  3rd  (  4*5-3)  or  (17) ,  sum  is  37  ok