Question 191488
<font face="Garamond" size="+2">

The perimeter of any polygon is simply the sum of the lengths of the sides.


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left( 5x^2+1\right ) + \left( 20x+4 \right) + \left( x^2+11x\right )]


Collect terms:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x^2 + x^2 + 20x + 11x + 1 + 4]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6x^2 + 31x + 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6 \times 1 = 6\ ,\ 5 \times 1 = 5\ ,\ 6 \times 5 + 1 \times 1 = 31]


So,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (6x + 1)(x + 5)]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>