Question 191432
A)  75=(x-5)*(t+2)                                                                      
b)  75=(x+5)*(t)                                                 
                                                                             
a=b )          x*t+5t=x*t + 2*x - 5*t -10
                   
                    5*t = -5*t + 2*x -10

                   5*t  + 5*t  = 2*x -10

                  10 *t   +10  = 2* x
            
                  5*t +5  = x

subst  in ( b )     75 =  (( 5*t+5)+(5)) *t

                          75 = ( 5*t+10) *t












                         0= 5*t^2 + 10*t - 75

                        0 = ( 5*t = 25 )  * ( t-3)

                       t= -5  Not Real       and    t= +3

subst          5*3  +5  = x

                   x = 20       ANSWER


 check      75 = ( 20-5) * (3+2)  =  15 * 5  = 75     ok  

check                 75 = ( 20 + 5) * (3) = 25 * 3  =  75     ok