Question 191414
To find the points of discontinuity for {{{y=(x^2+x-6)/(3x^2-12)}}}, simply set the denominator {{{3x^2-12}}} equal to zero and solve for "x". The solutions that you get for the equation {{{3x^2-12=0}}} will make the denominator zero. Since division by zero is undefined, these values are NOT in the domain (which leads to a discontinuity at that point). 



Do the same for {{{y=x/(x^2-9)}}} to find the points of discontinuity. Let me know if you need further help with this.