Question 26501
y=-0.02x^2+x
There are many ways to find the maximum height depending
on the math course you are taking.
Yours is a quadratic equation with a=-0.02 and b=1
The max point can be found at x=-b/2a =-1(1/-0.04)=25
Then height=y=-0.02(25)^2+25
y=12.5
Thought you might like to see this curve: the following.
*[invoke quadratic "x",-.02,1,0]
Cheers,
Stan H.