Question 21675
1st: x^2-5x=4
x^2-5x-4=0
Use the quadratic formula to get:
*[invoke quadratic "x",1,-5,-4]
2nd:
(x+2)(x-3)(x-6)=0
For this product to be zero one of these factors must be zero, so:
x+2=0 or x-3=0 or x-6=0
So, x=-2 or x=3 or x=6

Cheers,
Stan H.