<PRE><B>Question 191205</B>
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The sum of all the numbers from 5 to 10 &lt;i&gt;&lt;b&gt;exclusive&lt;/b&gt;&lt;/i&gt; is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \sum_{i=6}^{9}{\,i}\ =\ \frac{(6+9)4}{2} = 30]


The only perfect square in the range 5 to 10 is 9, so subtract 9 from the sum above:


30 - 9 = &lt;i&gt;&lt;b&gt;21&lt;/b&gt;&lt;/i&gt;


Read the question &lt;i&gt;&lt;b&gt;carefully&lt;/b&gt;&lt;/i&gt;.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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