Question 26468
1. Since the problem says the equation is parallel to x + 3y = 5. It is true that the slopes are equal, so lets find the slope(m) of the given equation:

a. solve for y:
 x + 3y = 5 subtact x from both sides
 3y = -x + 5 (I switched the position from 5-x, but the signs are correct)now divide both sides by 3

 y= (-x/3)+(5/3)  so m=-1/3

2. Now that we've found the slope(-1/3) and we have a point(-1,4) we can use the point-slope equation. Lets do this:

a. y-y1=m(x-x1) (point-slope) plug in the m,y1,and x1
b. y-(4)= (-1/3)(x-(-1)) do the math
c. y-4 = -x/3 + (1/3)    add 4 to both sides

so the equation is  y = -x/3 + 11/3