Question 190987
The modulus of the complex number a+bi is
|a+bi| = {{{sqrt(a^2+b^2)}}}

So
|2i|= |0+2i| = {{{sqrt(2^2+0^2)}}}= {{{sqrt(2^2)}}}= 2
|5 + 12i|= {{{sqrt(5^2+12^2)}}}= {{{sqrt(169)}}}= 13
|2 - 2i| = {{{sqrt(2^2+(-2)^2)}}}= {{{sqrt(8)}}}= {{{2sqrt(2)}}}
|1 - 4i| = {{{sqrt(1^2+(-4)^2)}}}= {{{sqrt(17)}}}