Question 190977
A  -B  + C = 1
2A -2B + 0 = 0
3A +B  -3C = 2 
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Subtract 2 times the 1st from the 2nd; Subtract 3 times the 1st from the 3rd:
A  -B  + C = 1
0  +0  -2C = -2
0  +4B -6C = -1 
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The 2nd equation tells us that C = 1
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Substitute that into the 3rd equation to solve for "B":
4B - 6 = -1
4B = 5
B = 5/4
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Substitute those values into the 1st equation to solve for "A":
A - (5/4) + 1 = 1
A = 5/4
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Cheers,
Stan H.