Question 190916
Graph, find center, vertices, co-vertices and foci.
9x^2+4y=36
y = (-9/4)x^2 + 9
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It's not a circle ; it's a parabola
There is no center and no co-vertices.
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Vertex form by squaring the x-terms:

9(x-0)^2 = -4(y-9)
(x-0)^2 = (-4/9)(y-9)
h = 0; k = 9
4p = -4/9
p = -1/9
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Vertex: (0 , 9)
Focus (0 , 80/9)
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Cheers,
Stan H.